Write the function itob(n ,s , b) that converts the integer n into a base b character representation in the string s.In particular, itob(n, s, 16) formats n as a hexadecimal integer in s.

/*itob: convert n to characters in s - base b    */
void itob(int n, char s[], int b){
     int i, j, sign;
     void reverse(char s[]);
     
     if ((sign = n) < 0)
         n = -n ;     /* record sign  */
     i = 0;
     do{
              /* generate digits in reverse order */
          j = n % b;         /* get next digit */
          s[i++] = ( j <= 9) ? j + '0' : j + 'a' - 10;
     } while (( n /= b) > 0);  /* delete it */
    if (sign < 0)
         s[i++] = '-';
    s[i] = '\0';
    reverse(s);
}